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| | | | Joined: Jan 2007 Posts: 202 Wrench Fetcher | | Wrench Fetcher Joined: Jan 2007 Posts: 202 | Its been bored .040 over and was just wondering what the cubes would be? Should be getting close to 300 cu in I would think. With a 4.125 stroke it should be a puller. | | | | | Joined: Nov 2005 Posts: 6,100 'Bolter | | 'Bolter Joined: Nov 2005 Posts: 6,100 | Hy Henry G I come up with 297.7888, so lets call it a 298, hope that helps. | | | | | Joined: Feb 2000 Posts: 5,237 'Bolter | | 'Bolter Joined: Feb 2000 Posts: 5,237 | Displacement = pi/4 x bore(2) x stroke x number of cylinders
pi/4 = 0.7853982
Thats; bore (squared)
Have fun, Joe
Last edited by Joe H; 12/09/2007 6:42 PM.
| | | | | Joined: Mar 2002 Posts: 9,115 'Bolter | | 'Bolter Joined: Mar 2002 Posts: 9,115 | All you need to do is figure out the volume change and add it on. The change would be (.040" /original dia bore). Multiply the result by 292 and you have the increase. For instance if the original bore was 3.5", then the change would be ((.040/3.5)* 292) which works out to 3.337 cu in. I think the figure in the posting above is what you will get. | | | | | Joined: Nov 2004 Posts: 117 Wrench Fetcher | | Wrench Fetcher Joined: Nov 2004 Posts: 117 | pi x r2 (radius squared) X h (stroke) x no. of cylinders.
cgresham1212
If you don't drive it, why have it?
55 1st Series 3100 5 window
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