not quite, super250, but hold that thought so you remember that 6v requires heavier gauge wires than 12v
Stuart, sci-fi can be fun!!
I been sidetracked, but pruning trees leaves time to think, that's fun too, even if it's a puzzle
what the original question concerned, was the heat created by increasing the resistance [why does the switch get hot], so tho I did mention lowered voltage, in fact the voltage [push] available to
the circuit hasn't changed, but we're 'burning' some of the current in the resistor - it may be that in the theory this can be explained as the voltage [potential work] being split between the 2 items, but it's the current that's 'working'
is it the voltage or current that burns your finger
somebody's law:
"The quantity of resistance in an electric circuit determines the amount of current flowing in the circuit for any given voltage applied to the circuit." - the way I understand that is if we introduce the added resistance of the switch to the circuit, we reduce the amount of current to the fan [actually 'burn some'], because we have an unchanging voltage applied to
the circuit - a lower voltage at the motor may be a theoretical reason the motor turns slower, but in terms of the circuit, especially the heat in the switch [the question], it's the current that's important - the amount of current supplied by the battery is partly used in the 'heat work' [joules, to bring in another dead guy] in the switch, leaving enough current to create half as much 'motional work' [torque] in the motor [and it's non linear resistance!]
I think Kirchoff's thing includes equality of currents to and from a point, as well as equality of potential differences - if my switch starts getting hotter than usual do I check to see if my battery is 14V?
this just reminds me that I was successful as a tech, dealing w/ the practical workings of electronics, but I packed it in because of the explanations of theory, maybe I should just ignore the electrical questions!
