OK, this question comes from working on a Seagrave V-12 engine, but I think it may still apply to Chevys, so I'm throwing it out there. AND, it's driving me nuts trying to figure out.

Setting the timing on this V-12. HUGE distributor with TWO rotors in it, 2 sets of points, 2 condensors, and 2 coils. Set up like 2 six-cylinder engines running side-by-side.

Anyway, my chosen method of setting static timing is to use my continuity tester tone on my MultiMeter. I hook one side up to the hot wire, either at the coil or the distributor, and the other to ground. Then, turning the distributor, I find the point when the tone just goes out, indicating points just opening.

At least, that's how I THOUGHT I did it. This time, I got tone even when the points were CLEARLY open. The ignition switch was definately off. This being a fire truck, there are 2 ignition sets, so I had 4 sets of points to try this on. It was unanimous.

Took one of the distributors out of the truck, and set the points in the vice, with the continuity tester - no problem. So HOW is the coil primary grounded with the ignition off? headscratch Are the primary and secondary windings in the coil by necessity connected, at least enough to get continuity? Or am I missing something? I thought it was the breaking of the primary current that triggered the secondary, so how is it triggered if there's always continuity?

Matter of resistance?! Somebody educated me . . .

-Michael


Please type slow, as I can't read very fast.

1939 Chevy/Central Fire Engine
1941 Chevy/American Fire Engine
1950 Chevy/American Fire Engine
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