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Comments about the steel bracket are based on a lack of knowledge about the forces involved and the strength of steel. Figure you want to stop a 5000 lb truck decelerating at a rate of 1G (50mph to stopped in just under 84 feet). That means you have to generate 5000 lbs of stopping power. Say you only want to do this with the front axle because your back axle brakes have failed. Say you are using 11" diameter disk brakes with center of disk pad at 10" diameter (5inch radius)
Using your 5000 lb stopping force / 2 disks = 2500 lbs / disk. Lets say your tires are 30 inches tall = 15 inch radius, therefore your brakes must create 15inch x 2500 lbs = 37,500 in-lbs of braking torque. Take this same torque and apply it at the caliper location and you get . . . 37,500 / 5 = 7500 lbs.
Even a poorly constructed 10guage bracket will hold 7500 lbs. . . . brackets are the easy part as far as strength goes, the hard part is designing them so they allow the caliper to float for even pad wear.
