Nope it won’t
A good meter reads RMS not linear average
1/3 duty cycle is
12 squared
Then average that
Then take the square root
That’s the number you will get for a old fashion iron vane meter
And the same value you will get for a modern decent meter that is true RMS

Junk meter assume a sine wave and give you all sorts of silly number
But no meter will give you the linear average


Edit: 1/3 duty square wave at 12V peak will give you 6.93v on a true RMS meter
It’s because RMS is about the equivalent DC required to preform the same work (or rate of energy transfer)
Voltage X Current is Watts (joules / second) aka the rate of work
But current is also proportional to voltage for a fixed load
So averaging only the voltage is insufficient to extract the effective DC equivalent voltage value of an arbitrary waveform, it requires the Root Mean Square value to compare it to DC
-s

Last edited by 2ManyTrucks; 09/03/2024 12:50 AM.